0551671
若a+x2=2008,b+x2=2009,c+x2=2010,且abc=24,则abc+bac...
解答:解:∵a+x2=2008,b+x2=2009,c+x2=2010,∴可知a=b-1,c=b+1,又∵abc=24,则abc+bac+cab-1a-1b-1c=(a b)2+(a c)2+(b c)22abc∴将a=b-1,...
解答:解:∵a+x2=2008,b+x2=2009,c+x2=2010,∴可知a=b-1,c=b+1,又∵abc=24,则abc+bac+cab-1a-1b-1c=(a b)2+(a c)2+(b c)22abc∴将a=b-1,...