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十进制下,(n+1)!比n!多两位数时,n的最小值为何整数...
比(x-1)!增加的位数不超过n, 所以要增加n+1位，那么至少需要x\ge10^n。而x!比(x-1)!增加n+1位，代表\frac{\ln\Gamma(x)}{\ln...6528,6530,6531,6532,6533,6534,6536,6537,6538,6539,6541,6542,6543,6544,6546,6547,6548,6549,6550,6552,6553,6554,6555,6557,6558,6559...