hlt6000s nut-1000
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n1=hL'x'n°(ga△)°=hL/a=NuT2=ML-L2M520-02LD2T-362M2L-2T-2L42T-202=M1+b2+C21-3+02+62-C2+2-62T-32-C2-12→b2=0,c2=-1,d2=1/2,a2=3/2各系数乘以2...50+(50-11)=44.5解:2C,P=990.3kg=0.641/(mk),=6065×10*,r=2382.7×10人g,设流动为层流,1.13h=Lu,L(t-t)1.13982383×1099032×06417L606.5×10-6×1.5×11=49548m)4hLt...