ipad ￡dt
￡(0~2x+1)f(t)dt=x^3+1/8求f(x+1) 谢了,不过f(2x+1)=(3...
答：(0→2x+1) ∫f(t)dt=x^3+1/8 (令t=2m,t=0,m=0；t=2x+1,m=x+1/2)(0→x+1/2) ∫f(2m)d(m/2)=x^3+1/8(0→x+1/2) ∫f(2m)dm...
￡(0~2x+1)f(t)dt=x^3+1/8求f(x+1)
答：(0→2x+1) ∫f(t)dt=x^3+1/8 (令t=2m，t=0，m=0；t=2x+1，m=x+1/2)(0→x+1/2) ∫f(2m)d(m/2)=x^3+1/8 (0→x+1/2) ∫f(2m...