sinxcosx+1+sin4x
²»¶¨»ý·Ösinxcosx/1+sin4x dx
2008-03-05 ¡Òsinxcosx/(1+sin^4x)dx 156 2014-12-22 Çó(sinxcosx)/(1+(sinx)^4)µÄ²»¶¨»ý·Ö 2017-04-25 Çósin x*cos x/(1+sin^4 x)µÄ²»¶¨»ý·Ö 2013-03-28 ¡Òsinx/(1+sin^4x) dxÔõô×ö°¡? 2012-04-27 1/(sinxcos^4x)µÄ²»¶¨»ý·Ö 51
²»¶¨»ý·ÖÌâÇósinxcosx/1+sin^4xµÄ»ý·Ö
¡Ò sinxcosx/(1 + sin⁴x) dx= ¡Ò sinx/(1 + sin⁴x) dsinx= (1/2)¡Ò 1/[1 + (sin²x)²] dsin²x= (1/2)arctan(...
(sinx+cosx)/(1+sin^4x)µÄ²»¶¨»ý·ÖÔõôËã? ¡¾sinx+...
ÕâÁ½²¿·ÖÏà¼ÓµÃµ½1/(1+x^4£©µÄ²»¶¨»ý·Ö
ÒÑÖªº¯Êýf(x)=cos4x - 2sinxcosx - sin4x.(1)Çóf(x)µÄµ¥µ÷...
(1)f(x)=cos4x-2sinxcosx-sin4x=(cos2x+sin2x)(cos2x-sin2x)-sin2x=cos2x sin2x=2cos(2x+¦Ð4),Áî2k¦Ð ¦Ð¡Ü2x+¦Ð4¡Ü2k¦Ð,Ôòk¦Ð 5¦Ð8¡Üx¡Ük¦Ð ¦Ð8,...
ÈçºÎÇó 1/(sinx+cosx) µÄ²»¶¨»ý·Ö?
dt = -\sin xdx\frac{\sin^5x}{\cos^4x}dx = -\frac{\sin^4x}{\cos^4x}d\cos x = -\frac{(1-t^2)^2}{t^4}dt\int\frac...
ÒÑÖªsinx+cosx=m(m²»µÈÕý¸º1)Çó1.sin^3x+cos^3x2.sin^...
ÓÉsinx+cosx=m,¿ÉÖªsinxcosx=(m^2-1)/2(1)sin³x+cos³x=(sinx+cosx)[(sinx)^2+(cosx)^2-sinxcosx]=m(1-...
»»Ôª·¨ ¡Òsinxcosx/(1+sin^4x) dx
¡Òsinxcosx/(1+sin^4x) dx=1/2*arctan(sin^2x)+C¡£CΪ³£Êý¡£»»Ôª·¨¼ÆËã¡Òsinxcosx/(1+sin^4x) dxµÄ¹ý³ÌÈçÏ£ºËùÒÔ¡Òsinxcosx/(1+sin^4x) dx=1/2...
²»¶¨»ý·ÖÌâ Çósinxcosx/1+sin^4xµÄ»ý·Ö
¡Ò sinxcosx/(1 + sin⁴x) dx = ¡Ò sinx/(1 + sin⁴x) dsinx = (1/2)¡Ò 1/[1 + (sin²x)²] dsin²x = (1/2)arc...
ÈçºÎ²»Çóµ¼Çó cosx+sinx µÄ×î´óÖµ?
sinxËùÒÔÈý´Î·½µÄºÍСÓÚµÈÓÚÆ½·½µÄºÍ¼´Ð¡ÓÚµÈÓÚ1ËùÒÔÁ½¸öÈý´Î·½µÄºÍ×î´óÖµÖ»ÄÜÊÇ1µ±sinx¡¢cosx¡Ù0Óɸ¨Öú½Ç¹«Ê½f(x)=sqrt£¨sin^4x+cos...
...2)f(x)=lgsinx+cosxsinx - cosx;(3)f(x)=1+sinx...
(1)f(x)=sin(34x+3¦Ð2)=-cos34x,ÓÐf(-x)=-cos(-34x)=-cos34x=f(x),Ôòf(x)Ϊżº¯Êý;(2)ÓÉsinx+cosxsinx-cosx>0,¼´Îªtanx+1tanx-1>0,¿ÉµÃ tanx<...