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sin15¶È cos15 tan15·Ö±ðÊǶàÉÙ,Ó÷ֺűíʾ

sin15˚ = (¡Ì6 - ¡Ì2)/4cos15˚ = (¡Ì6 + ¡Ì2)/4tan15˚ = 2 - ¡Ì3


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tan15¶ÈÔõôËã?

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tan15¶ÈÔõôËã

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tan15¶ÈÊǶàÉÙ?

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